Madhya Pradesh Police Exam Model Paper 8

Given:
If the length and breadth of a rectangle are in the ratio 3 : 2 and its perimeter is 20 cm.
Concept used:
Area of rectangle = Length × Breadth
Perimeter of rectangle = 2(Length + Breadth)
Calculation:
Let the length of the rectangle be 3x
Breadth of the rectangle be 2x.
Area of the rectangle will be $6{\mathit{x}}^{2.}$
Perimeter of the rectangle is $2\left(\mathit{L}+\mathit{B}\right)$
Perimeter $=2\left(3\mathit{x}+2\mathit{x}\right)$
Perimeter = 10x
$\Rightarrow 10\mathit{x}=20$
$\Rightarrow \mathit{x}=2$
Length = 6cm and Breadth = 4 cm
Area of rectangle $=6{\mathit{x}}^2$
⇒ Area $=6\times 4$
∴ Area $=24\mathit{c}{\mathit{m}}^2$ .