Madhya Pradesh Police Exam Model Paper 8

A close up of a keyboard Description automatically generated
According to the positional values of the alphabets,
1) AE6 → A = 1, E = 5 → A × E = 1 × 5 = 5 ≠ 6
2) AK11 → A = 1, K = 11 → A × K = 11.
3) CD12 → C = 3, D = 4 → C × D = 12.
4) BM26 → B = 2, M = 13 → B × M = 26.
Hence, the odd one among the given options is AE6.