Madhya Pradesh Police Exam Model Paper 6

Given:
A Geometric Progression with first term ‘a’ = 16 and common ratio ‘r’ = 2.
Concept Used:
In this type of question, where ‘r’ > 1, then the sum of n terms of a G.P= ${\mathit{S}}_{\mathit{n}}=\frac{\mathit{a}\left({\mathit{r}}^{\mathit{n}}-1\right)}{\mathit{r}-1}$
Formula Used:
${\mathit{S}}_{\mathit{n}}=\frac{\mathit{a}\left({\mathit{r}}^{\mathit{n}}-1\right)}{\mathit{r}-1}$
n = 10
Calculation:
Considering the given series
16, 32, 64, 128, ......
${\mathit{S}}_{10}=\frac{16\left(2^{10}-1\right)}{2-1}$
$\Rightarrow {\mathit{S}}_{10}-16\times 1023=16368$
∴ Sum of first 10 terms of given series is 16368