Madhya Pradesh Police Exam Model Paper 4

Question : 71 of 100

Marks: +1, -0

The degree of the polynomial

(2x-1)(2x+1)(4x^2+1)(16x^4+1)

in its standard form is:

Solution:

Given:

(2x-1)(2x+1)(4x^2+1)(16x^4+1)

Formula Used:

(a-b)(a+b)=(a^2-b^2)

Calculation:

(2x-1)(2x+1)(4x^2+1)(16x^4+1)

⇒[(2x^2-1^2)](4x^2+1)(16x^4+1)

⇒(4x^2)^2-1^2)(16x^4+1)

⇒(16x^4-1)(16x^4+1)

⇒[(16x^4)^2-1^2]

⇒(256x^8-1)

⇒ degree = 8
∴ Degree of the polynomial
$(2x-1)(2x+1)(4x^2+1)(16x^4+1)$
in its standard form is 8.

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