If x=1983 !, then the value of the expression \frac{1}{\log _{2} x}+\frac{1}{\log _{3} x}+\frac{1}{\log _{4} x}+. . . . . .+\frac{1}{\log _{1983} x} is equal to

Logarithms

Question : 43 of 85

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x=1983 !

, then the value of the expression

\;{1}/{\log _{2} x}+\;{1}/{\log _{3} x}+\;{1}/{\log _{4} x}+. . . . . .+\;{1}/{\log _{1983} x}

is equal to

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