If {\log x}/{a^{2}+a b+b^{2}}= {\log y}/{b^{2}+b c+c^{2}}= {\log z}/{c^{2}+c a+a^{2}} then x^{a-b} \cdot y^{b-c} \cdot z^{c-a}=

Logarithms

Question : 33 of 85

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\;{\log x}/{a^{2}+a b+b^{2}}=\;{\log y}/{b^{2}+b c+c^{2}}=\;{\log z}/{c^{2}+c a+a^{2}}

then

x^{a-b} ⋅ y^{b-c} ⋅ z^{c-a}=

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