\frac{\log x}{l+m-2 n}=\frac{\log y}{m+n-2l}=\frac{\log z}{n+l-2 m}, then the value of x^{2} y^{2} z^{2} is :

Logarithms

Question : 24 of 85

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\;{\log x}/{l+m-2 n}=\;{\log y}/{m+n-2l}=\;{\log z}/{n+l-2 m},

then the value of

x^{2} y^{2} z^{2}

is :

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