Linear Inequalities

Question : 38 of 54

Marks: +1, -0

A fertilizer company produces two types of fertilizers called Grade I and Grade II. Each of these types is processed through two critical chemical plant units.
Plant A has maximum 120 hrs available in a week and Plant B has maximum of

180 {hrs}

available in a week.
Manufacturing one bag of grade I fertilizer requires 6 hours in Plant

A

and 4 hours in Plant B.
Manufacturing one bag of Grade II fertilizer requires 3 hrs in Plant

A

and 10 hours in Plant B.

$6 x+3 y ≤ 120,4 x+10 y=180$
$6 x+3 y=120,4 × 10 y>180$
$6 x+3 y ≤ 120,4 x+10 y ≤ 180$
$6 x+3 y < 120,4 x+10 y < 180$

Validate

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