LIC AAO 12 May 2013 Paper

Question : 60 of 160

Marks: +1, -0

In a container there are 28 eggs out of which 8 eggs are rotten. If two eggs are chosen at random, what will be the probability that atleast one egg is rotten ?

$94/189$
$95/187$
$93/189$
$97/189$
None of these

Validate

Solution:

Total possible outcomes= Selection of 2 eggs out of 28
=

↖{28}C_{2}

{28×27}/{1×2}

= 14 × 27
Favourable outcomes,
= Selecting 1 unrotten egg out 20 and 1 rotten egg out of 8 + selecting 2 rotten eggs out of 8
=

↖{20}C_1

↖{8}C_1

↖{8}C2

= 160 +

{8×7}/2

= 188
∴ Required probability =

{188}/{14×27}

{94}/{7×27}

{94}/{189}

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