LIC AAO 06 Mar 2016 Paper

Radius of circular field = r metre = Side of a square fieldAccording to the question
$\mathit{\pi }{\mathit{r}}^2$ - ${\mathit{r}}^2$ = 105
⇒ ${\mathit{r}}^2\left(\frac{22}{7}-1\right)$ = 105
⇒ ${\mathit{r}}^2\left(\frac{22-7}{7}\right)$ = 105
⇒ ${\mathit{r}}^2$ × $\frac{15}{7}$ = 105
⇒ ${\mathit{r}}^2$ = $\frac{105\times 7}{15}$ = 7 × 7
∴ r = $\sqrt{7\times 7}$ = 7 metre
∴ Circumference of circular field = 2πr
= 2 × $\frac{22}{7}$ × 7 = 44 metre