LIC AAO 05 Mar 2016 Paper

Question : 41 of 160

Marks: +1, -0

A boat can travel 12.6 km downstream in 35 minutes. If the speed of the water current is 1/4 th the speed of the boat in still water, what distance (in km) can the boat travel upstream in 28 minutes ?

Validate

Solution:

Rate downstream of boat
=

{\Distance}/{\Time}

({12.6}/{{35}/{60}})

kmph
=

{12.6×60}/{35}

= 21.6 kmph
Speed of current = x kmph (let)
∴ Speed of boat in still water = 4x kmph
∴ 4x + x = 21.6
⇒ 5x = 21.6
⇒ x =

{21.6}/5

= 4.32 kmph
∴ Rate upstream of boat = 3x
= 3 × 4.32 = 12.96 kmph
∴ Required distance =

({12.96×28}/{60})

km = 6 km

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