KVPY SX SB Exam 2018 Question Paper

Nitroglycerine (MW = 227.1) detonates according to the following equation :
$2{\mathit{C}}_3{\mathit{H}}_5{\left(\mathit{N}{\mathit{O}}_3\right)}_3\left(\mathit{l}\right)\to 3{\mathit{N}}_2\left(\mathit{g}\right)+\frac{1}{2}{\mathit{O}}_2\left(\mathit{g}\right)$ $+6\mathit{C}{\mathit{O}}_2\left(\mathit{g}\right)+5{\mathit{H}}_2\mathit{O}\left(\mathit{g}\right)$ The standard molar enthalpies of formation, $∆{\mathit{H}}_{\mathrm{f}}^{\mathit{o}}$ for all the compounds are given below :
$∆{\mathit{H}}_{\mathrm{f}}^{\mathit{o}}\left[{\mathit{C}}_3{\mathit{H}}_5{\left(\mathit{N}{\mathit{O}}_3\right)}_3\right]=\mathit{–}364$ kJ/mol
$∆{\mathit{H}}_{\mathrm{f}}^{\mathit{o}}\left[\mathit{C}{\mathit{O}}_2\left(\mathit{g}\right)\right]=\mathit{–}393.5$ kJ/mol
$∆{\mathit{H}}_{\mathrm{f}}^{\mathit{o}}\left[{\mathit{H}}_2\mathit{O}\left(\mathit{g}\right)\right]=\mathit{–}241.8$kJ/mol
$∆{\mathit{H}}_{\mathrm{f}}^{\mathit{o}}\left[{\mathit{N}}_2\left(\mathit{g}\right)\right]=0$kJ/mol
$∆{\mathit{H}}_{\mathrm{f}}^{\mathit{o}}\left[{\mathit{O}}_2\left(\mathit{g}\right)\right]=0$kJ/mol
The enthalpy change when 10 g of nitroglycerine is detonated is