KVPY SX SB Exam 2016 Question Paper

Question : 97 of 120

Marks: +1, -0

The heat capacity of one mole an ideal is found to be

CV = 3R (1 + aRT)/2

where a is a constant. The equation obeyed by this gas during a reversible adiabatic expansion is -

Solution:

Adiabatic process

\TV^{γ-1}=C

γ=1+2/f

\TV^{2/f}=C

C_V={fR}/2={3R(1+aRT)}/2

{fR}/2={3Re^{aRT}}/2

2/f=2/{3e^{aRT}}

TV^{2/{3e^{aRT}}}=C

TV^{{{3e^{aRT}}/2}}=C

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