KVPY SX SB Exam 2016 Question Paper

Question : 55 of 120

Marks: +1, -0

It takes 1h for a first order reaction to go to 50% completion. The total time required for the same reaction to reach 87.5% completion will be

Solution:

t_{1\/2}=1\hr

t_87.5=2.303/k\log a/{a-x}

=2.303/{0.693/1}\log a/{a-0.875}

=2.303/{0.693/1}\log 8

=2.303/{0.693/1}×3×0.3010=3

Go to Question:

Prev Question

Next Question