KVPY SX SB Exam 2016 Question Paper

Question : 110 of 120

Marks: +1, -0

The specific conductance of 0.02 M aqueous acetic acid solution at 298 K is

1.65 × 10^{–4 } \S \cm^{–1}

. The degree of dissociation of acetic acid is [Given : equivalent conductance at infinite dilution of H

^{+}

= 349.1 \S \cm^2 \mol ^{–1}

and

\CH_3\COO^{–} = 40.9 \S \cm^2\mol^{–1}

]

Solution:

λ_M={1000×K}/M

={1000×1.65×10^{-4}}/0.2

= 8.25

λ_H^{∞}=λ_M^{∞}(H^{+}+λ_M^{∞}(CH_3COO^{-}))

= 349.1 + 40.9 = 390
specific conductance

=8.25/390=0.0211

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