KVPY SX SB Exam 2016 Question Paper

Question : 107 of 120

Marks: +1, -0

For electroplating, 1.5 amp current is passed for 250 s through 250 mL of 0.15 M solution of MSO

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. Only 85% of the current was utilized for electrolysis. The molarity of MSO

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solution after electrolysis is closest to [Assume that the volume of the solution remained constant]

Solution:

No. of mole

={i×t}/{96500×v.f}

⇒n×v.f={i×t}/96500×n

={1.5×250}/{96500×2}×0.85

n = .00165 (deposited)

n_i={250×0.15}/1000=0.0375(\initial \mole )

n_\left = .03585

(mole left)

M_\left=0.03585/0.25 =0.143

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