KVPY SX SB Exam 2015 Question Paper

Question : 63 of 120

Marks: +1, -0

Assume a spherical mammalian cell has a diameter of 27 microns. If a polypeptide chain with alpha helical conformation has to stretch across the cell, how many amino acids should it be comprised of?

18000
1800
27000
12000

Validate

Solution:

No. of amino acid in one term in α helix = 3.6
Pitch length for α Helix = 5.4 Aº
∴ The No. of Amino acid in polypeptide

=3/6/{5.4 ×10^{-10}}×27×10^{-6}

1.8 × 10^4

Amino acid = 18000 amino acid

Go to Question:

Prev Question

Next Question