KVPY SX SB Exam 2015 Question Paper

Question : 31 of 120

Marks: +1, -0

A simple pendulum of length

l

is made to oscillate with an amplitude of 45 degrees. The acceleration due to gravity is g. Let

T_0 = 2π√{l \/ g}

. The time period of oscillation of this pendulum will be -

T $_0$ irrespective of the amplitude
slightly less than T $_0$
slightly more than T $_0$
dependent on whether it swings in a plane aligned with the north-south or east-west directions

Solution:

T_0 = 2π√{l /g}(1+θ^2/16)

(This is valid when θ is not small)

T_0 = 2π√{l /g}

(for small θ)

T=T_0(1+θ^2/16)

T > T_0

Go to Question:

Prev Question

Next Question