KVPY SX SB Exam 2015 Question Paper

Question : 106 of 120

Marks: +1, -0

An organic compound having molecular formula

C_2H_6O

undergoes oxidation with

K_2Cr_2O_7\/H_2SO_4

to produce X which contains 40% carbon, 6.7% hydrogen and 53.3% oxygen. The molecular formula of the compound X is

Solution:

\table { CH_3–CH_2–OH}↙{(C_2H_60)},{–––––––––––▸}↖{K_2Cr_2O_7\/H_2SO_4},CH_3–{C↙{∥}}↙{\O}–O–H;\Alcohol,,\Carboxylic \acid;(C_nH_{2n+2} O),,\Total \wt = 60;,,C = 24 (40% /carbon);,,O = 32 (53.3%);,,H = 4 (6.7%)

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