KVPY SX SB Exam 20141 Question Paper

Question : 56 of 120

Marks: +1, -0

The number of moles of KMnO

_4

required to oxidize one equivalent of KI in the presence of sulfuric acid is

Solution:

KMnO_4 + KI + H_2SO_4\ {––––––▸} MnSO_4 + I_2 + K_2SO_4 + H_2O

v.f = 5
v.f = 1
∴ (eq)

_{\KMnO_4}

=(eq)

_{ \KI}

= 1
Eq. = V.F. × mole
1 = 5 × mole
Mole =

1/5

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