KVPY SX SB Exam 20141 Question Paper

Question : 51 of 120

Marks: +1, -0

The equilibrium constant

K_c

of the reaction, 2A ⇌ B + C is 0.5 at 25 °C and 1 atm. The reaction will proceed in the backward direction when concentrations [A], [B] and [C] are, respectively

$10^{-3}, 10^{-2}$ and 10 $^{-2}$ M
$10^{-1}, 10^{-2}$ and 10 $^{-2}$ M
$10^{-2}, 10^{-2}$ and 10 $^{-3}$ M
$10^{-2}, 10^{-3}$ and 10 $^{-3}$ M

Validate

Solution:

Q = {[B][C]}/[A^2 ]

K_C = 0.5

For option (A)

Q={(10^{-2})×(10^{-2})}/[10^{-3}]^2=100

Q > K_C

i.e. reaction proceed in backward direction.

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