KVPY SX SB Exam 20141 Question Paper

Question : 35 of 120

Marks: +1, -0

Two identical parallel plate capacitors of capacitance C each are connected in series with a battery of emf, E as shown. If one of the capacitors is now filled with a dielectric of dielectric constant k, the amount of charge which will flow through the battery is (neglect internal resistance of the battery)

${k+1}/{2(k-1)}CE$
${k-1}/{2(k+1)}CE$
${k-2}/{ k+2}CE$
${k+2}/{ k-2}CE$

Validate

Solution:

New charge on each

C =({kC}/{k+1})

Change in charge on C is supplied by battery
∴ Charge supply by battery =

=({kC}/{k+1})E-{CE}/2

⇒

CE[k/{k+1}-1/2]

⇒

CE[{k-1}/{2(k+1)} ]

Charge passes through battery is change supply by battery
∴ Ans.

CE[{k-1}/{2(k+1)} ]

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