KVPY SX SB Exam 20141 Question Paper

Question : 28 of 120

Marks: +1, -0

An ideal gas follows a process described by

PV^2 =C

from

(P_1, V_1, T_1) \to\ (P_2, V_2, T_2)

(C is a constant). Then

Solution:

PV^2 = C

⇒

({nRT}/V)V^2=C

⇒ TV = C \;\;\;\;⇒ T_1V_1 = T_2V_2

⇒ If temperature increases, volume decreases and vice versa
⇒

V_2 > V_1 \then T_2 < T_1.

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