KVPY SX SB Exam 20141 Question Paper

Question : 24 of 120

Marks: +1, -0

A simple pendulum is attached to a block which slides without friction down an inclined plane (ABC) having an angle of inclination a as shown.

While the block is sliding down the pendulum oscillates in such a way that at its mean position the direction of the string is

Solution:

mg[1 -\sin^2 α] ⇒ mg\cos^ 2 α

\tan θ ={mg\cos^ 2 α}/{mg\sinα \cosα}

\tan θ = \cot α

\tan θ = \tan (90 -α)

θ = (90 -α)

string is perpendicular to inclined plane .

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