KVPY SX SB Exam 2013 Question Paper

Question : 7 of 120

Marks: +1, -0

Let ABC be an acute-angled triangle and let D be the midpoint of BC. If AB = AD, then

{\tan(B)}/{\tan(C)}

equals

Solution:

Using M - N Rule
(1 + 1) cot (π - B) = 1.cot B - cot C
3 cot B = cot C

{\tan \B}/{\tan \C}=3

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