KVPY SX SB Exam 2013 Question Paper

Question : 46 of 120

Marks: +1, -0

For the reaction,

A ⇌ n B

the concentration of A decreases from 0.06 to 0.03 mol

\L^{ -1}

and that of B rises from 0 to 0.06 mol

\L^{ -1}

at equilibrium. The values of n and the equilibrium constant for the reaction, respectively, are

Solution:

\table ,\A,⇌,\nB;t=0,0.06,,0;t=t,0.03,,0.06

αc = 0.03
nαc = 0.06
n = 2

\K_\C=(0.06)^2/0.03=0.12

Go to Question:

Prev Question

Next Question