KVPY SX SB Exam 2012 Question Paper

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Question : 58 of 120

Marks: +1, -0

The ecuilibrium constant for the following reactions are

K_{1}

and

{K}_{2}

, respectively.

2 {P}(g)+3 {Cl}_{2}(g) ⇌ 2 {PCl}_{3}(g)

{PCl}_{3}(g)+ {Cl}_{2}(g) ⇌ {PCl}_{5}(g)

Then the equilibrium constant for the reaction

2 P(g)+5 C l_{2}(g) ⇌ 2 P C l_{5}(g)

is

$K_1K _2$
$K_1K _2^2$
$K_1^2K _2^2$
$K_1^2K _2$

Solution:

2 {P}( {g})+3 {Cl}_{2}( {g}) 2 {PCl}_{3}( {g}) {K}_{1}

2 {PCl}_{3}( {g})+2 {Cl}_{2}( {g}) 2 {PCl}_{5}( {g}) {K}_{2}{ }^{2}

Net reaction :

2 {P}( {g})+5 {Cl}_{2}( {g}) 2 {PCl}_{5}( {g})

{K}= {K}_{1} {K}_{2}{ }^{2}

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