KVPY SX SB Exam 2012 Question Paper

Question : 53 of 120

Marks: +1, -0

The pKa of a weak acid is 5.85. The concentrations of the acid and its conjugate base are equal at a pH of

Solution:

\pH =\pKa+\log[\Comjugate\base]/[\Acid]

∵ [Conjugate base] = [Acid]
pH = pKa = 5.85

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