KVPY SX SB Exam 2012 Question Paper

Question : 26 of 120

Marks: +1, -0

In a Young’s double slit experiment the intensity of light at each slit is

I_0

. Interference pattern is observed along a direction parallel to the line

S_1, S_2

on screen S.

The minimum, maximum, and the intensity averaged over the entire screen are respectively

Solution:

I_{max}=(√{I_{0}}+√{I_{0}})^{2}=4 I_{0}

I_{min} =(√{I_{0}}-√{I_{0}})^{2}=0

I_{avg}=(I_{0}+I_{0})=2 I_{0}

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