KVPY SX SB Exam 2012 Question Paper

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Question : 13 of 120

Marks: +1, -0

The value of

∫↖{2012}↙{-2012}(\sin(x^3)+x^5+1)dx

is

2012
2013
0
4024

Solution:

∫↖{2012}↙{-2012}(\sin(x^3)+x^5+1)dx

∫↖{2012}↙{-2012}(\sin (x^3)dx)

+∫↖{2012}↙{-2012}x^5dx+∫↖{2012}↙{-2012}dx

= 4024

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