Consider the following nuclear reactions: I. { }_{7}^{14} {N}+{ }_{2}^{4} {He} \rightarrow{ }_{8}^{17} {O}+X II. { }_{4}^{9} {Be}+{ }_{2}^{4} {H} \rightarrow{ }_{6}^{12} {He}+Y Then,

Correct Answer is : X is a proton and Y is a neutron.

X is a neutron and Y is a proton

KVPY SX SB Exam 19-Nov-2017 Question Paper

Question : 33 of 120

Marks: +1, -0

Consider the following nuclear reactions:
I.

{ }_{7}^{14} {N}+{ }_{2}^{4} {He} ⟶{ }_{8}^{17} {O}+X

II.

{ }_{4}^{9} {Be}+{ }_{2}^{4} {H} ⟶{ }_{6}^{12} {He}+Y

Then,

Solution:

Balancing given nuclear reactions, we get

{ }_{7}^{14} {N}+{ }_{2}^{4} {He} ⟶{ }_{8}^{17} {O}+{ }_{1}^{1} X

and

\;\; { }_{4}^{9} {Be}+{ }_{2}^{4} {H} ⟶{ }_{6}^{12} {He}+{ }_{0}^{1} Y

So,

X

is a proton and

Y

is a neutron.

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