KVPY SX SB Exam 19-Nov-2017 Question Paper

Question : 26 of 120

Marks: +1, -0

A rope of mass 5 kg is hanging between two supports as shown. The tension at the lowest point of the rope is close to (take g = 10 m/s

^{2}

)

Solution:

∴ 2T

_1

cos 30° = mg = 5 × 10 = 50.
2T

_1

cos 30° = 50

T = T

_1

sin 30°

=50/{{2√3}/2}.1/2=25/√3={25√3}/3

T = 14.41 N

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