KVPY SX SB Exam 05-Nov-2017 Question Paper

Question : 58 of 120

Marks: +1, -0

A reaction has an activation energy of 209 kJ mol

^{-1}

. The rate increases 10–fold when the temperature is increased from 27°C to X °C. The temperature X is closest to [Gas constant, R = 8.314 J mol

^{-1}

K^{-1}

]

Solution:

\log_10 = {209 ×10^3}/{2.303 ×8.314}[1/300-1/T]

9.16 × 10^{–5} = 3.33 × 10^{–3}-1/T

T = 308.4 K
or 35º C = X

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