KVPY SX SB Exam 05-Nov-2017 Question Paper

Question : 56 of 120

Marks: +1, -0

Mg(OH)

_2

is precipitated when NaOH is added to a solution of Mg

^{2+}

. If the final concentration of Mg

^{2+}

is 10

^{–10}

M, the concentration of OH

^{–}

(M) in the solution is [Solubility product for Mg (OH)

_2 = 5.6 × 10^{–12}]

Solution:

K_{ sp} Mg(OH)_2 = [Mg^{+2}] [OH^{–}]^2

5.6 × 10^{–12} = [10^{–10}][OH^{–}]^2

[OH^{– }] = √{5.6× 10 ^{-2}} = 0.24 M

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