KVPY SX SB Exam 05-Nov-2017 Question Paper

Question : 38 of 120

Marks: +1, -0

A particle of mass m moves around the originin a potential

1/2mω^2r^2

, where r is the distance from the origin. Applying the Bohr model in this case, the radius of the particle in its nth orbit in terms of a

= √{h /(2π mω) }

Solution:

mvr = n h/{2π}

v = rω

mr^ 2 ω = nh/{2π}

r=√{{nh^2}/{2πmω}}

r=√n√{h^2/{2πmω}

r=√n.a

Go to Question:

Prev Question

Next Question