Let \f(x) = \max \{3,x^2,1/x^2\} \for 1/2\leq x \leq 2. Then the value of the integral \int^{2}_{1\/ 2}\f(x)dx is

KVPY SX SB Exam 05-Nov-2017 Question Paper

Question : 19 of 120

Marks: +1, -0

Let

\f(x) = \max \{3,x^2,1/x^2\} \for 1/2≤ x ≤ 2

. Then the value of the integral

∫↖{2}↙{1\/ 2}\f(x)dx

Solution:

Given Integral can be distributed into

∫↖{1\/√3}↙{1\/2}1/x^2.dx+∫↖{ √3}↙{1\/√3}3dx+∫↖{2}↙{√3}x^2.dx =14/3

Go to Question:

Prev Question

Next Question