KVPY SX SB Exam 05-Nov-2017 Question Paper

Question : 115 of 120

Marks: +1, -0

Molecular weight of E. Coli DNA is 3.1 × 10

^{9}

g/mol. Average molecular weight of nucleotide pair is 660 g/mol and each nucleotide pair contributes to 0.34 nm to the length of DNA. The length of E. coli DNA molecule will be approximately

0.8 nm
1.6 nm
1.6 µm
1.6 mm

Validate

Solution:

Molcular weight of E.coli DNA is

3.1 × 10^{9} {g} \/ {mol}

.
Molecular weight of DNA = Number of base pairs

\times

average molecular weight of nucleotide pair.
Therefore, number of base pairs = molecular weight of DNA / average molecular weight of nucleotide pair

=3.1 × 10^{9} \/ 660=4.70 × 10^{6} .

One base pair contributes of

0.34 {nm}

length.
Hence,

4.70 × 10^{6}

base pair contributes to

4.70 × 10^{6} × 0.34=1.6 × 10^{6} {nm}=1.6 {mm} .

Go to Question:

Prev Question

Next Question