Let A = \{\theta \in R | \cos^2(\sin\theta) + \sin^2 (\cos\theta) = 1\} and B = \{\theta \in R | \cos(\sin\theta)\sin(\cos\theta) = 0\}. Then A\capB

Correct Answer is : is the empty set

has more than one but finitely many elements

KVPY SB SX Exam 2011 Question Paper

Question : 85 of 120

Marks: +1, -0

Let

A = \{θ ∈ R | \cos^2(\sinθ)

+ \sin^2 (\cosθ) = 1\}

and

B = \{θ ∈ R | \cos(\sinθ)\sin(\cosθ) = 0\}

. Then

A∩B

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