KVPY SB SX Exam 2011 Question Paper

Question : 57 of 120

Marks: +1, -0

In a zero-order reaction, if the initial concentration of the reactant is doubled, the time required for half the reactant to be consumed

Solution:

K={A_0-A_t}/t

K=A_2/{2t_{1\/2}}

t_{1\/2}=A_0/{2K}

Zero order

t_{1\/2} ∝

initial concentration
so double times

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