KVPY SB SX Exam 2011 Question Paper

Question : 49 of 120

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When the size of a spherical nanoparticle decreases from 30 nm to 10 nm. the ratio surface area/volume becomes

Solution:

\text"Surface area"/\Volume={πd^2}/{{πd^3}/6}=6/d

d_1

= 30 nm,

d_2

= 10 nm

(\text"Surface area"/\Volume)_2/(\text"Surface area"/\Volume)_1={6/d_2}/{6/d_1}

=d_1/d_2=30/10=3

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