KVPY SB SX Exam 2011 Question Paper

Question : 32 of 120

Marks: +1, -0

For a domestic AC supply of 220 V at 50 cycles per second, the potential difference between the terminals of a two-pin electric outlet in a room is given by

$V(t) = 220√2\cos( 100πt)$
$V(t) = 220 \cos( 50t)$
$V(t) = 220 \cos( 100πt)$
$V(t) = 220√2 \cos( 50t)$

Validate

Solution:

R.M.S. value = 220 V
Peak value =

220 √2

ω = 2πn = 2π × 50 = 100 π

\V(t) = 220√2\cos( 100\πt)

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