KVPY SB SX Exam 2011 Question Paper

Question : 23 of 120

Marks: +1, -0

If the speed (v) of the bob in a simple pendulum is plotted against the tangential acceleration (a), the correct graph will be represented by

Solution:

In SHM

a = - ω^2x

v=ω√{A^2-x^2}

v^2=ω^2(A^2-x^2)

v^2=ω^2A^2-ω^2×a^2/ω^2

v^2+a^2/ω^2=ω^2A^2

v^2/{ω^2A^2}+a^2/{ω^4A^2}=1

i.e. ellipse

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