KVPY SB SX Exam 2011 Question Paper

Question : 17 of 120

Marks: +1, -0

Two players play the following game: A writes 3, 5, 6 on three different cards; B writes 8, 9, 10 on three different cards. Both draw randomly two cards from their collections. Then A computes the product of two numbers he/she has drawn, and B computes the sum of two numbers he/she has drawn. The player getting the larger number wins. What is the probability that A wins?

$1/3$
$5/9$
$4/9$
$1/9$

Validate

Solution:

For A to win, A can draw either 3, 6 or 5, 6. If A draws 3, 6 then B can draw only 8 & 9
Prob.

=1/3 . 1/3=1/9

If A draws 5, 6 the n B can draw, any two Probability

= 1/3 . 1=1/3

Probability

=1/9+1/3=4/9

Go to Question:

Prev Question

Next Question