KVPY SA Exam 2018 Question Paper

Question : 43 of 80

Marks: +1, -0

The formal oxidation numbers of Cr and Cl in the ions

Cr_2O_7^{2– }

and

Cl O_3^{–}

respectively, are

Solution:

Oxidation number of Cr in

Cr_2O_7^{2– } = + 2x -14 = -2

⇒ x = + 6

Oxidation number of Cl in

Cl O_3^{–} = x -6 = -1

⇒ x = + 5

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