KVPY SA Exam 2016 Question Paper

Question : 9 of 80

Marks: +1, -0

Let P be a point inside a triangle ABC with ∠ABC = 90°. Let

P_1

and

P_2

be the images of P under reflection in AB and BC respectively. The distance between the circumcenters of triangles ABC and

P_1PP_2

Solution:

M is circumcentre of ΔABC

⇒M(a/2,b/2)

& N is circumcentre of ΔABC
N = (0, 0) = B (Mid-point of

P_1

, &

P_2

).
So MN

=\AC/2

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