KVPY SA Exam 2016 Question Paper

Question : 6 of 80

Marks: +1, -0

Let ABCD be a trapezium, in which AB is parallel to CD. AB =11, BC = 4, CD = 6 and DA = 3, The distance between AB and CD is

Solution:

Solve

a^2 + h^2 = 9

....(1)
and

(6 - a)^2 + h^2 = 16

....(2)
we will get h = 2.4

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