KVPY SA Exam 2016 Question Paper

Question : 4 of 80

Marks: +1, -0

Consider the equation

(1 + a + b )^2 = 3(1 + a^2 + b^2)

. where a, b are real numbers, Then

Solution:

(1 + a + b)^2 = 3 (1 + a^2 + b^2)

⇒1 . a + a . b + 1 . b

= 1^2 + a^2 + b^2

⇒ 1 = a = b

exactly one pair.

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