KVPY SA Exam 2016 Question Paper

Question : 20 of 80

Marks: +1, -0

Water falls down a 500.0 m shaft to reach a turbine which generates electricity. How much water must fall per second in order to generate

1.00 × 10^9

Watts of power? (Assume 50 % efficiency of conversion and

g= 10 \m \s ^{-2}

)

Solution:

P={mah}/\time

\η=\P_\out/\P_\intput

⇒\P_\in=\P_\out/\η

=10^9/0.5=2×10^9

m/t={2×10^9}/{10×500}=2/5×10^6

= 4 × 10^5= 400 \m^3

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