KVPY SA Exam 2016 Question Paper

Question : 18 of 80

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A car goes around uniform circular track of radius R at a uniform speed v once in every T seconds. The magnitude of the Centripetal acceleration is

a_c

. If the car now goes uniformly around a larger circular track of radius 2R and experiences a centripetal acceleration of magnitude

8a_c

. then its time period is

Solution:

∴ Time period

={(2\π)R'}/\V'

={(2π)2R}/{4\V}

={π\R}/\V=T/2

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