KVPY SA Exam 2015 Question Paper

Question : 8 of 80

Marks: +1, -0

Let ABCD be a square of side length 1, and a circle passing through B and C , and touching AD. The radius of circle is

Solution:

Let O be centre of circle.
OM = radius = r

∴ r^2=(1-r)^2+(1/2)^2

⇒

2r -1 =1/4

⇒ 2r=5/4

⇒

r= 5/8

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